SOLUTION: In how many ways can the first, second and third place winners be selected from 8 contestants?

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Question 1192636: In how many ways can the first, second and third place winners be selected from 8
contestants?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52824) About Me  (Show Source):
You can put this solution on YOUR website!
.

In 8*7*6 = 336 different ways.

It is the product of three consecutive integers in descending order starting from 8.

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See the lesson
    - Special type permutations problems

in this site. Find there many solved similar problems.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
In how many ways can the first, second and third place winners be selected from 8
contestants?
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Why would winners be "selected?"