SOLUTION: In a baseball tournament consisting of twelve teams, in which each team plays every other team once, how many games will there be? Multiple choice answers: a. 15 b. 720 c.

Algebra ->  Permutations -> SOLUTION: In a baseball tournament consisting of twelve teams, in which each team plays every other team once, how many games will there be? Multiple choice answers: a. 15 b. 720 c.      Log On


   



Question 1161690: In a baseball tournament consisting of twelve teams, in which each team plays every other team once, how many games will there be?
Multiple choice answers:
a. 15
b. 720
c. 24
d. 66

Found 2 solutions by solver91311, greenestamps:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Team 1 plays against 2, 3, 4,...,11, 12, a total of 11 teams

Team 2 plays against 1, 3, 4,...,11, 12, also 11 teams, but we already counted 2 vs. 1 when we counted Team 1's opponents. Hence, 10 teams.

Similarly, Team 3 plays against 11 teams, but 2 of those have already been counted, so 9 teams.

And so on. In summary:

Team  1      11
Team  2      10
Team  3       9
Team  4       8
Team  5       7
Team  6       6
Team  7       5
Team  8       4
Team  9       3
Team 10       2
Team 11       1
Team 12       0


So



You can do your own arithmetic.


John

My calculator said it, I believe it, that settles it


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Each game is between 2 of the 12 teams. The number of games is

C%2812%2C2%29+=+%2812%2A11%29%2F%282%2A1%29+=+132%2F2+=+66