SOLUTION: How many different committees of 5 people can be chosen from 10 people?

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Question 1081515: How many different committees of 5 people can be chosen from 10 people?
Found 3 solutions by Edwin McCravy, josmiceli, jim_thompson5910:
Answer by Edwin McCravy(20056) About Me  (Show Source):
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10 people, choose 5 = 10C5 = 252

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
C( 10,5 ) = +10%21+%2F+%285%21%2A%28++10-5+%29%21%29+
C( 10,5 ) = +10%21+%2F+%285%21%2A5%21%29+
C( 10,5 ) = +10%2A9%2A8%2A7%2A6+%2F+%285%2A4%2A3%2A2%2A1%29+
C( 10,5 ) = +252+
252 different committees
check the math


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Use the combination formula (nCr) to get...

n C r = (n!)/(r!(n-r)!)

10 C 5 = (10!)/(5!*(10-5)!)

10 C 5 = (10!)/(5!*5!)

10 C 5 = (10*9*8*7*6*5*4*3*2*1)/((5*4*3*2*1)*(5*4*3*2*1))

10 C 5 = (3628800)/((120)*(120))

10 C 5 = (3628800)/(14400)

10 C 5 = 252


Answer: 252