SOLUTION: for each of the two successive years bean prices rose by 10% . at the beginning of the first year 1 kg of bean cost $20 .at the end of the second year how many grams of bean could
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-> SOLUTION: for each of the two successive years bean prices rose by 10% . at the beginning of the first year 1 kg of bean cost $20 .at the end of the second year how many grams of bean could
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Question 829934: for each of the two successive years bean prices rose by 10% . at the beginning of the first year 1 kg of bean cost $20 .at the end of the second year how many grams of bean could be bought for $50 Answer by LinnW(1048) (Show Source):
You can put this solution on YOUR website! at the end of one year, the price of 1kg of beans is (1+10%)(20)
= 1.10*20 = 22
at the end of year 2, the price of 1kg of beans is (1+10%)(22)
= 1.10*22 = 24.2
So we can purchase 1KG of beans for $24.20.
Solving for KG/dollar 1KG/24.20 = (1/24.2)KG/dollar
$50(1/24.2)= 2.066116KG = 2.0661 grams
