SOLUTION: Employees use two methods to refinidh a chair. Method I takes 1 hour and cost $3. Method II takes 1 1/2 hour and cost $1.50. Last week, they took 36 hours and spen t $60. How m
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-> SOLUTION: Employees use two methods to refinidh a chair. Method I takes 1 hour and cost $3. Method II takes 1 1/2 hour and cost $1.50. Last week, they took 36 hours and spen t $60. How m
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Question 70382: Employees use two methods to refinidh a chair. Method I takes 1 hour and cost $3. Method II takes 1 1/2 hour and cost $1.50. Last week, they took 36 hours and spen t $60. How many did they refinish with each method? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Employees use two methods to refinidh a chair. Method I takes 1 hour and cost $3. Method II takes 1 1/2 hour and cost $1.50. Last week, they took 36 hours and spen t $60. How many did they refinish with each method?
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Let "x" be number done with Method I.
Yet "y" be number done with Method II.
Time equation: 1x + 1.5y = 36
Cost Equation: 3x + 1.5y = 60
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Subtract time equation from cost equation to get:
2x=24
x=12 (number done with Method I)
Substitute into time equation to solve for y as follows:
12 + 1.5y = 36
1.5y = 24
y = 16 (number done with Method II)
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Cheers,
Stan H.
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