SOLUTION: in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fra

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fra      Log On


   

Question 656289: in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fraction
Found 2 solutions by stanbon, shweta:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fraction
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Let the numerator be "x".
Then denominator is "x-7"
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Equation:
(x+3)/(x-7+3) = 15/8
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(x+3)/(x-4) = 15/8
8x + 24 = 15x - 60
7x = 84
x = 12
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Fraction: x/(x-7) = 12/5
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Cheers,
Stan H.
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Answer by shweta(56) About Me  (Show Source):
You can put this solution on YOUR website!
Let the fraction be N/D

D= N-7(given)
fraction:N/N-7 ..1
When N+3/D+3 = 15/8

N+3/N-7+3 =15/8
N+3/N-4 = 15/8
On cross- multiplication,
8*(N+3) = 15*(N-4)
8N+ 24 = 15N - 60
24+60 = 15N -8N
7N = 84
N= 84/7
N= 12
D= N-7
D= 12-7= 5
So the original fraction is 12/5