Question 610838: Suppose each of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is written on a separate poker chip and placed in a hat. If one of the chips is randomly selected, determine the probability that the chip selected will contain an odd number or a number less than five.
I am still not understanding this kind of math... Any help is appreciated...
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 ||Note:  chips in all, 2 Odds <5
Selecting one chip:
P(Odd 'or' number <5) = P(Odd)+ P(<5) - P(both) = 5/10 + 4/10 - 2/10 = 
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