SOLUTION: the ratio of sonnets to odes was 15 to 4. If six times the number of odes was 12 less than twice the number of sonnets,how many were odes and how many were sonnets?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: the ratio of sonnets to odes was 15 to 4. If six times the number of odes was 12 less than twice the number of sonnets,how many were odes and how many were sonnets?      Log On


   



Question 1065800: the ratio of sonnets to odes was 15 to 4. If six times the number of odes was 12 less than twice the number of sonnets,how many were odes and how many were sonnets?
Answer by ikleyn(52817) About Me  (Show Source):
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S%2FO = 15%2F4,           (1)

6*O = 2S - 12.     (2)    ( O is the number of odes )


From (1), S = O%2A%2815%2F4%29. Substitute it into (2) to get

6*O = 2%2AO%2A%2815%2F4%29-12  --->

24*O = 30*O - 48  --->

48 = 30*O - 24*O  --->  48 = 6*O  --->  O = 48%2F6 = 8.

Answer. 8 odes and 8%2A%2815%2F4%29 = 30 sonnets.