SOLUTION: I am trying to figure out how the area of a right trapezoid and the shorter base was calculated. From a diagram, the longer base is 8cm. The shorter base is unknown. The height is

Algebra ->  Parallelograms -> SOLUTION: I am trying to figure out how the area of a right trapezoid and the shorter base was calculated. From a diagram, the longer base is 8cm. The shorter base is unknown. The height is       Log On


   

Question 1136847: I am trying to figure out how the area of a right trapezoid and the shorter base was calculated. From a diagram, the longer base is 8cm. The shorter base is unknown. The height is 3 cm. The slant height is 5 cm. I do not know how the total area was calculated at 18cm (squared) and the shorter base was calculated at 4 cm.
Found 2 solutions by ikleyn, Theo:
Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
1.  Make a sketch.



2.  Your trapezoid has ONLY ONE obtuse angle.

    From the vertex of this obtuse angle draw the height (the perpendicular) to the longer base.



3.  You will obtain a right angled triangle.

    Do you see it ?


    Its hypotenuse is 5 cm.
    Its leg is 3 cm.

    Hence, its other leg is 4 cm (3-4-5 right angled triangle).



4.  Hence, the shorter base of the trapezoid is 8 - 4 = 4 centimeters.

    Is it clear so far ?



5.  To find the area of the trapezoid, use the basic formula


    Area of the trapezoid = %28%28a%2Bb%29%2F2%29%2Ah = %28%284+%2B+8%29%2F2%29%2A3 = 18 square centimeters.


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the longer base is equal to 8 cm.
the height is equal to 3 cm.
the slant height is equal to 5 cm.

if it is a right trapezoid, then two of the angles have to be right angles.

label your trapezoid ABCDE clockwise from top left.

angle A and angle E are right angles.

the slant height is side BC = 5.

the height is BD = 3 and AE = 3.

the triangle on the right is right triangle BCD where the 90 degree angle is BDC.

angles BDE and ABD are also right angles.

use pythagorus to find the length of DC, which is 4.

pythagorus says 3^2 + x^2 = 5^2

solve for x to get x = sqrt(5^2 - 3^2) = sqrt(16) = 4.

that makes ED = 4 and, consequently AB = 4 because ABDE forms a rectangle.

the area of the trapezoid is equal to the area of the rectangle plus the area of the triangle.

this becomes 4 * 3 + 1/2 * 3 * 4 which becomes 12 + 6 = 18.

here's my diagram.

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