SOLUTION: Let a and b are vectors such that Vector a = (1,1,2) Vector b = (2,-1,1) And let vector c be a unit vector such that triple product of a,b,c is minimum . We have to find the v

Algebra ->  Parallelograms -> SOLUTION: Let a and b are vectors such that Vector a = (1,1,2) Vector b = (2,-1,1) And let vector c be a unit vector such that triple product of a,b,c is minimum . We have to find the v      Log On


   

Question 1051048: Let a and b are vectors such that
Vector a = (1,1,2)
Vector b = (2,-1,1)
And let vector c be a unit vector such that triple product of a,b,c is
minimum . We have to find the value of c.
[Thoughts]
I thought triple product of a b, c means the volume occupied by
parrallropipe. And we have to do volume minimum
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Make a vector that lies in the plane created by the vectors a and b.
Then the thickness of your parallelpiped would be zero and you'd have achieve your volume minimum.
So then make c a linear combination of a and b.
c=m(1,1,2)+n(2,-1,1)
where m and n are real numbers.