|
Question 990525: Find three consecutive numbers whose sum is 99.
Answer by farohw(175) (Show Source):
You can put this solution on YOUR website!
Let x + (x + 1) + (x + 2) = 99 --> x + x + 1 + x + 2 = 99
Adding will yield, 3x + 3 = 99
3x + 3 = 99 --> 3x = 99 - 3 --> 3x = 96
3x/3 = 96/3
x = 32
The 3 consecutive numbers are 32, 33, 34.
Verify:
32 + 33 + 34 = 99
|
|
|
| |