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Question 935023: If 4 consecutive odd integers sum to 152, what is the smallest of the 4?
Answer by AlgebraLady88(44)   (Show Source):
You can put this solution on YOUR website! Let the first odd integer be x.
The second one would be x+2
The third one would be x+4
The fourth one would be x+6.
How do I know the second one is x+2? Just plug in 1 as the odd integer(x). For the second one, x+2= 3, then x+4= 5 and the last one, x+6=7. Try it with other odd integers and you will get the same results.
Now, we can solve algebraically
x+ (x+2) + (x+4) + (x+6) = 152
4x + 12 = 152
4x + 12 - 12 = 152-12
4x = 140
x = 35
So, the integers are 35, 37, 39 and 41. The smallest would be 35.
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