You can put this solution on YOUR website! Let a1= the first number
a2= the second number
d= 1
The sum of two consecutive numbers is 73.
Sn = n/2(2a1+(n-1)d)
73 = 2/2(2a1+(2-1)1)
73 = 2a1+1
72 = 2a1
36 = a1
a2 = a1+(n-1)d
a2 = 36+(2-1)1
a2 = 36+1
a2 = 37
The numbers are 36 and 37.
