Question 853841: The sum of two positive integers is 9. Twice the first integer plus thrice the second integer is 22. Determine the numbers Found 2 solutions by rothauserc, chndnbl:Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! we have two equations, let x be one positive integer and y be the other
x + y = 9
2x + 3y = 22
solve first equation for x and substitute in second equation
x = 9 - y
2(9-y) +3y = 22
18-2y +3y = 22
y = 4
x = 5
substitute in second equation
2*5 + 3*4 = 22
22 = 22
our answer checks :-)
You can put this solution on YOUR website! Let the positive integer be x and y.
From the first condition:
x + y = 9
from the second condition:
2x + 3y =22
multiplying 3 to equation (1).
3x + 3y =27
Then solving by elimination method .
x =5
then substituting the value of x in (1)
y=9-5=4
y=4
