Question 821471: one number is 4 less than three times the second number. their total is 64. find the numbers Found 2 solutions by balthazar612, ortarico:Answer by balthazar612(14) (Show Source):
You can put this solution on YOUR website! let numbers x and y
3x-y=4
X+y=64
Y is cancelled by adding both equations
4x= 68
X= 68/4
X = 17
Putting value of x in equation 1
4x-y=4
4*17 -y = 4
68- y = 4
Y = 68 -4
Y = 64
So numbers are 17 and 64
You can put this solution on YOUR website! Let the two numbers be denoted as 'a' and 'b'
From the first sentence: a = 3b - 4 eqn1
From the second sentence: a = 64 - b eqn2
equating eqn 1&2: 3b - 4 = 64 - b
3b b = 64 4
4b = 68
b = 17
Substitute b = 17 into eqn1:
a = 3b - 4
a = 3(17) - 4
a = 51 - 4
a = 47
:. The two numbers are 17&47
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