SOLUTION: The squares of two consecutive integers are added. The sum of their squares is 181. What are the integers?

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Question 802982: The squares of two consecutive integers are added. The sum of their squares is 181. What are the integers?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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The squares of two consecutive integers are added.
The sum of their squares is 181.
x^2 + (x+1)^2 = 181
x^2 + x^2 + 2x + 1 - 181 = 0
2x^2 + 2x - 180 = 0
Simplify divide by 2
x^2 + x - 90 = 0
Factors to
(x+10)(x-9) = 0
the positive solution
x = 9 is the 1st integer, 10 is the 2nd (obviously)

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