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Question 665465: one of the digits of a 2 digit no is 3 times the other digit.if you interchange the digits of this no it is found resulting is 2times the original no.what is the no?
Answer by kevwill(135)   (Show Source):
You can put this solution on YOUR website! Let the smaller digit be x and the larger digit be y. From the problem statement we are given that y = 3x.
The two-digit number is 10x + y, and reversing the digits gives 10y + x. We are told that reversing the digits doubles the original number, so
10y + x = 2(10x + y)
Substituting 3x for y into this equation gives:
10(3x) + x = 2(10x + 3x)
30x + x = 20x + 6x
31x = 26x
There are no non-zero values for x which make this equation true, so there is no solution to this problem as stated.
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