SOLUTION: A golf ball is hit into the air, and its height h in feet after t seconds is given by h(t) = -16t to the second power + 128t.
a) what is the height of the golf ball when it is hi
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a) what is the height of the golf ball when it is hi
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Question 626294: A golf ball is hit into the air, and its height h in feet after t seconds is given by h(t) = -16t to the second power + 128t.
a) what is the height of the golf ball when it is hit?
b) After how many seconds does the golf ball reach its maximum height?
c) Determine the maximum height of the golf ball? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A golf ball is hit into the air, and its height h in feet after t seconds is given by h(t) = -16t^2 + 128t.
:
a) what is the height of the golf ball when it is hit?
When the ball is hit, time, t = 0
h(t) = -16(0^2) + 128(0)
h(t) = 0 ft high when t=0
:
b) After how many seconds does the golf ball reach its maximum height?
Max height occurs at the axis of symmetry
Find the axis of symmetry of h = -16t^2+128t using the formula x = -b/(2a)
a=-16, b=128
t =
t =
t = 4 seconds to reach max height
:
c) Determine the maximum height of the golf ball?
Replace t with 4, find h(t)
h(t) = -16(4^2) + 128(4)
h(t) = -16*16 + 512
h(t) = -256 + 512
h(t) = 256 ft is the max height
:
Graphically, time on the x axis, height on the y axis
