Question 507740: The sum of the digits of a certain two certain numbers is 11 when reverse it's digits you increase the number number 45. Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! x + y = 11
x = 11-y
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10y + x = 10x+y+45
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10y + 11 -y = 10(11-y) + y + 45
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10y +11 -y = 110 -10y + y + 45
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9y + 11 = 155 -9y
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18y = 144
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y = 144/18
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y = 8
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x = 11-8
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x = 3
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So the original number was 38.
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If you reverse the digits, you have 83.
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38 + 45 = 83
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Correct.
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Answer: The original number was 38.
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Done.
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