SOLUTION: Find 3 consecutive odd integers whose sum is 43 (Hint: if n represents the smallest of the three integers, n+2 and n+4, represent the other two numbers)

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Question 445631: Find 3 consecutive odd integers whose sum is 43 (Hint: if n represents the smallest of the three integers, n+2 and n+4, represent the other two numbers)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of 3 consecutive integers, in order, odd, or even, is divisible by 3.
43 is not, so there's no solution
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If we pretend we don't know that:
n + n+2 + n+4 = 43
3n+6 = 43
3n = 37
n = 37/3, not an integer
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Examples:
9+11+13 = 33
23+25+27 = 75
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20+22+24 = 66
7+8+9 = 24
All the sums are divisible by 3