SOLUTION: Find 4 consecutive odd integers whose sum is 32. what is their equation and solution?

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Question 390352: Find 4 consecutive odd integers whose sum is 32. what is their equation and solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Every other number is an odd number, so
If I call the smallest odd number n, then
the 4 numbers are:
n, n%2B2, n+%2B+4, and n+%2B+6%7D%7D%0D%0A%7B%7B%7Bn+%2B+n+%2B+2+%2B+n+%2B+4+%2B+n+%2B+6+=+32
4n+%2B+12+=+32
4n+=+20
n+=+5
n+%2B+2+=+7
n+%2B+4+=+9
n+%2B+6+=+11
The numbers are 5,7,9, and 11
check answer:
4n+%2B+12+=+32
4%2A5+%2B+12+=+32
20+%2B+12+=+32
32+=+32
OK