Question 367744: The sum of two numbers is eleven. The sum of the squares of the two numbers is sixty-five. Find the two numbers. Found 3 solutions by Alan3354, aprilburchett, Edwin McCravy:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! First you must list all sums that will equal eleven:
10+1=11
9+2=11
8+3=11
7+4=11
6+5=11
Then you need to know which set of these numbers squared will equal 65:
10^2+1^2=100+1=101
9^2+2^2=81+4=85
8^2+3^3=64+9=73
7^2+4^2=49+16=65
6^2+5^2=36+25=61
You want the one that equals 65, so your two numbers are 6 and 5. They both add up to equal 11 and the sum of their squares is 65.
Solve the first one for y
Substitute for y in the second:
Simplify and get 0 on the right side
Divide every term by 2
Factor the left side:
Us the zero-factor principle:
x - 7 = 0 x - 4 = 0
x = 7 x = 4
Substitute in
y = 11 - x
If x = 7, then y = 11 - 7 or 4
If x = 4, then y = 11 - 4 or 7
So the numbers are 4 and 7.
Checking 4 + 7 = 11 and 4² + 7² = 16 + 49 = 65. So those answers
are correct.
Edwin