Question 330318: Using each of the digits 1,2,3,4,5, and 6 only once, find two - 3 digit numbers whose product is as large as possible. Answer by solver91311(24713) (Show Source):
Obviously one of the numbers must have 6 for a high order digit and the other must have 5 for the high order digit.
So far then, we have 2 numbers, 6xy and 5ab. Again, it is obvious that we need to put the 4 and the 3 into the x and a positions, but which goes where? Intuitively, it would make sense for the 5 to be followed by 42 because that would maximize the number that is being multiplied by the number beginning with the 6. Let's check out the 4 possibilities:
Largest.
John
My calculator said it, I believe it, that settles it
