Question 316925: find the lessor of two consecutive intergers with a sum greater than 16.
Answer by tinbar(133)   (Show Source):
You can put this solution on YOUR website! x+(x+1)>16
2x+1>16
2x>15
x>15/2
therefore, any x>7.5 works since 7.5+8.5=16
since u need Integers though, pick x = 8, since 8+9>16
don't pick x = 7, since 7+8<16
so the lesser of the two would be 8 while the greater of the two would be 9
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