SOLUTION: Let a and b represent digits. for the number 31a,59b,076 to be divisible by 3, a + b must be a) a multiple of 3. b) 1 less than a multiple of 3. c) 1 more than a multiple

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Question 283853:
Let a and b represent digits. for the number 31a,59b,076 to be divisible by 3,
a + b must be
a) a multiple of 3. b) 1 less than a multiple of 3.
c) 1 more than a multiple of 3 d) a multiple of 12
e) cannot be determined.
Answer by checkley77(12844) About Me  (Show Source):
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Answer B)
The sum of all digits must equal a multiple of 3.
The sum of the known digits is:
3+1+5+9+7+6=31
Adding 1 less than 3=2 you get 31+2=33.
33 is a multiple of 3.