|
Question 273778: find 3 consecutive odd integers such that the square of the first increased by the product of the other two is 224
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! find 3 consecutive odd integers such that the square of the first increased by the product of the other two is 224
:
" 3 consecutive odd integers"
x, (x+2), (x+4)
:
"such that the square of the first increased by the product of the other two is 224"
x^2 + ((x+2)(x+4)) = 224
FOIL
x^2 + x^2 + 6x + 8 = 224
:
2x^2 + 6x + 8 - 224 = 0
:
2x^2 + 6x - 216 = 0
:
Simplify, divide by 2
x^2 + 3x - 108 = 0
:
Factors to
(x+12)(x-9) = 0
:
positive solution
x = 9, the 1st odd integer
:
Check using the integers, 9, 11, 13
9^2 + 11*13 =
81 = 143 = 224
:
What about the solution x=-12? It satisfies the equation but,it's an even value
|
|
|
| |
