SOLUTION: the second of two numbers is 4 times the first. their sum is 50. find the number i dont understand the question at alllll. :(

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Question 226269: the second of two numbers is 4 times the first. their sum is 50. find the number
i dont understand the question at alllll. :(
Found 2 solutions by drj, Abyssalanine:
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website!
The second of two numbers is 4 times the first. Their sum is 50. Find the number.

Step 1. Let x be the first number.

Step 2. Let 4x be the second number since it is 4 times the first.

Step 3. Let x+4x=50 be the sum of the two numbers and is given as 50.

Step 4. Solving the equation in Step 3 leads to the following steps.

Divide by 5 to both sides of the equation to get x

and . Also, the sum of 10 and 40 is 50 as a check of the solution.

Step 5. ANSWER: The numbers are 10 and 40.

I hope the above steps were helpful.

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And good luck in your studies!

Respectfully,
Dr J

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Answer by Abyssalanine(3) (Show Source):
You can put this solution on YOUR website!
Two of the numbers are Number 1 : (N1), and Number 2 : (N2).
Both numbers add up to equal 50.
N1 + N2 = 50
One is 4 times the other; for example I will use (N2).
N2 = 4(N1)
Substitute N2 in with 4(N1).
N1 + 4N1 = 50
5N1 = 50
5N1/5 = N1
50/5 = 10
N1 = 10
Substitute N1 with 10.
10 + N2 = 50
10 - 10 = 0
50 - 10 = 40
N2 = 40
In the end, the two numbers are 10 and 40.