SOLUTION: an objects altitude in meter, is given by the polynomial h+ vt-9.8t^2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per sec
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Question 225214: an objects altitude in meter, is given by the polynomial h+ vt-9.8t^2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second and t is the number of seconds for which the rocket is airborne. a pebble is shot upward from the top of a building 164 tall. if the intial speed is 36 meters per second, how high above the ground will the pebble be after 3 seconds. round results to the nearest tenth of a meter. Answer by LtAurora(115) (Show Source):
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Given the intial equation and the constants, we can simply plug them in:
Solving this yields:
This height is in addition to the 164 meters of the building, so
The pebble is 183.8 m above the ground at .
