SOLUTION: I have tried multiple times to solve this problem, but each time I get the wrong answer ( I've checked in the back of the book).
Question: " The difference of two numbers is 67.
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Question: " The difference of two numbers is 67.
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Question 210519This question is from textbook Intermediate Algebra
: I have tried multiple times to solve this problem, but each time I get the wrong answer ( I've checked in the back of the book).
Question: " The difference of two numbers is 67. The larger number is three less than six times the smaller number. Find the numbers."
I tried solving it like this:
x-y=67
larger number=6y-3
(6y-3)-y=67
The answers in the back of the book says 14 and 81. I am so lost in how they found that answer. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! The difference of two numbers is 67. The larger number is three less than six times the smaller number. Find the numbers."
I tried solving it like this:
x-y=67
larger number=6y-3
(6y-3)-y=67
The answers in the back of the book says 14 and 81.
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Since x-y = 67, the "x" must be the larger number.
Equation:
x = 6y-3
-----------------------
Substitute that into x-y=67 to get:
6y-3 - y = 67
5y = 70
y = 14
-------
Substitute that and solve for "x":
x = 6*14 -3
x = 84-3
x = 81
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Cheers,
Stan H.
You can put this solution on YOUR website! Question: " The difference of two numbers is 67. The larger number is three less than six times the smaller number. Find the numbers."
I tried solving it like this:
x-y=67
larger number=6y-3
(6y-3)-y=67
---------------
14 and 81 does work.
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x = larger #
y = smaller #
------------
x-y = 67
x = 6y-3
Sub for x into the 1st eqn
(6y-3) - y = 67
5y = 70
y = 14
x = 81
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