SOLUTION: if the sum of three consecutive odd integers is 237 then what are the integers

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Question 155746: if the sum of three consecutive odd integers is 237 then what are the integers
Found 2 solutions by stanbon, Electrified_Levi:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
if the sum of three consecutive odd integers is 237 then what are the integers
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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EQUATION:
2x-1 + 2x+1 + 2x+3 = 237
6x + 3 = 237
6x = 234
x = 39
-----------
1st: 2x-1 = 77
2nd: 79
3rd: 81
==============
Cheers,
Stan H.

Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
hi, hope I can help,
.
if the sum of three consecutive odd integers is 237 then what are the integers
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This is a pretty easy problem
First, you have to know the variables
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consecutive means "in order" (example: 1, 2, 3, ... ) here is another example: (25, 26, 27, ... )
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consecutive odd means "in order, but they have to be odd numbers" (examples: 3, 5, 7, 9, ... ) or ( 107, 109, 111, 113, ... )
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Since this is our first number, we can name it "x"
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Our second number would be "x+2" ( we have three consecutive odd integers ,meaning, if the first number is odd, you have to add 2 more to get the next odd number( example: let's say our "x" was 5, our second number would be "x+2", we replace "x" it will become "5+2" or "7", our first odd number is 5, our second is 7)
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Our third number is "x+4" (if second number is odd, have to add 2 to get the third odd number
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Your first number will always be "x"
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If you are trying to find the consecutive numbers(not consecutive odd), you add 1 for each number ( first number = "x", second = "x+1", third = "x+2", fourth = "x + 3", ... )
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If you are finding consecutive odd( or even) numbers, you add 2 for each number
( first number always = "x") ( first number = "x", second number = "x + 2", third number = "x + 4", fourth number = "x + 6", ... )
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Since we are finding consecutive odd integers, our three numbers are( remember we start with "x" and add 2 each time)
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First number = "x"
Second number = "x + 2"
Third number = "x + 4"
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Since we know our three variables, we can know put them in a formula
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if the sum of three consecutive odd integers is 237 then what are the integers
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First number = "x"
Second number = "x + 2"
Third number = "x + 4"
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Our fomula = +%28x%29+%2B+%28x+%2B+2%29+%2B+%28x+%2B+4%29+=+237+
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Now all we need to do is solve for "x"
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We can get rid of the parentheses, +x+%2B+x+%2B+2+%2B+x+%2B+4+=+237+
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We will reorder the numbers, +x+%2B+x+%2B+x+%2B+4+%2B+2+=+237+
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we will now combine like terms
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+%28x+%2B+x+%2B+x%29+%2B+%284+%2B+2%29+=+237+ = +3x+%2B+6+=+237+
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we will now move "6" to the right side
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+3x+%2B+6+-+6+=+237+-+6+ = +3x+=+231+
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We will divide each side by "3" to get "x"
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+3x%2F3+=+231%2F3+ = +x+=+231%2F3+ = +x+=+77+
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We found that our first odd consecutive number(x) = 77
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Our second number = "x + 2" ( replace "x" with 77) = "77 + 2" = 79
Our third number = "x + 4" ( replace "x" with 77) = "77 + 4" = 81
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We can check by replacing "x" with 77 in our original equation
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+%28x%29+%2B+%28x+%2B+2%29+%2B+%28x+%2B+4%29+=+237+
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+%2877%29+%2B+%2877+%2B+2%29+%2B+%2877+%2B+4%29+=+237+
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+%2877%29+%2B+%2879%29+%2B+%2881%29+=+237+
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+237+=+237+ ( True )
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Our three numbers are
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1st = +77+
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2nd = +79+
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3rd = +81+
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Hope I helped, Levi