SOLUTION: Find three consecutive odd integers of which one half of the sum of the first and second equals the square of the difference of the third and the first.
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Question 155017: Find three consecutive odd integers of which one half of the sum of the first and second equals the square of the difference of the third and the first. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Integers=x, x+2, x+4
(x+x+2)/2=(x+4-x)^2
(2x+2)/2=4^2
2(x+1)/2=16
x+1=16
x=16-1
x=15 the smallest integer.
15+2=17 the next one.
15+4=19 the largest.
proof:
(15+17)/2=(19-15)^2
32/2=4^2
16=16
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