Question 1195355: one number is 8 more than twice another. their sum is 62. what are the numbers?
Found 4 solutions by Alan3354, etutornow.com, greenestamps, dezbee2008:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! one number is 8 more than twice another. their sum is 62. what are the numbers?
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L - larger
S - Smaller
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L = 2S + 8
L + S = 62
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2S + 8 + S = 62
3S = 54
etc
You can put this solution on YOUR website! let
1st no x
2nd no y
given condition
x+y=62---1 equation
x=2y+8---2 equation
then 2y=x-8 from eq 2
=>y=x-8/2
y=(x-8)/2
x+ x-8/2=62 from eq 1
=>2x+x-8=62x2
=>3x=124+8
=>3x=132
=>x=132/3=>44
x=44
y=x-8/2 from eq--2
y=44-8/2
=>y=36/2=>18
y=18
x+y=62 from eq 1
44+18=62 [x=44 and y=18]
62=62 proved
The solution from the other tutor, using two variables, is fine; but a solution using a single variable usually leads to a faster solution with less work.
x = first number
2x+8 = second number (8 more than twice the first)
The sum of the two numbers is 62:
x+2x+8=62
3x+8=62
3x=62-8=54
x=54/3=18
ANSWERS: The two numbers are x=18 and 2x+8=36+8=44
You can put this solution on YOUR website! Let's determine our numbers first
n = first number
2n+8 = 8 more than twice the number
62 = sum of the two numbers
Put the equation together: n+2n+8=62
Combine like terms: 3n+8=62
Subtract 8 from both sides: 3n=54
Divide 3 by both sides: n=18
Plug 18 into the original equation: 18+2(18)+8=62
Solve using order of operations: 18+36+8=62
54+8=62
62=62
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