SOLUTION: The product of two consecutive odd integers is 1 less than 5 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers

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Question 1194141: The product of two consecutive odd integers is
1
less than
5
times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
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The product of two consecutive odd integers is
1
less than
5
times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
-----------------------

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The product of two consecutive odd integers is 1 less than
5 times their sum. Find the two integers.
=======================================================================

Integers n and n+2
n%28n%2B2%29=-1%2B5%28n%2B%28n%2B2%29%29
n%5E2%2B2n=-1%2B5%282n%2B2%29
n%5E2%2B2n=10n%2B10-1
n%5E2=8n%2B9
n%5E2-8n-9=0
%28n-9%29%28n%2B1%29=0
system%28n=-1%2Cor%2Cn=9%29-----------and you can now find the two possible pair of integers.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The product of two consecutive odd integers is 1 less than 5 times their sum.
Find the two integers.
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n*(n+2) + 1 = 5(n + n+2)
n^2 + 2n + 1 = 10n + 10
n^2 - 8n - 9 = 0
(n-9)*(n+1) = 0
n = 9
---> n & 11
=============
n = -1
---> -1 & +1