SOLUTION: Find three consecutive integers such that the sum of the largest and four times the second is 42 more than the first.

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Question 1090559: Find three consecutive integers such that the sum of the largest and four times the second is 42 more than the first.
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
system%28n-1%2Cn%2Cn%2B1%29, but not the only way

%28n%2B1%29%2B4n=42%2B%28n-1%29, Solve for n, first.