SOLUTION: A delivery of 5 large boxes and 2 small boxes has a total weight of 88 kilograms. A delivery of 3 large boxes and 8 small boxes has a total weight of 97 kilograms. How much does

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: A delivery of 5 large boxes and 2 small boxes has a total weight of 88 kilograms. A delivery of 3 large boxes and 8 small boxes has a total weight of 97 kilograms. How much does       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 941529: A delivery of 5 large boxes and 2 small boxes has a total weight of 88 kilograms. A delivery of 3 large boxes and 8 small boxes has a total weight of 97 kilograms. How much does each type of box weigh?
Found 2 solutions by macston, ankor@dixie-net.com:
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
5L+2S=88kg
3L+8S=97kg
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++5%5CL+%2B+2%5CS+=+88%2C%0D%0A++++3%5CL+%2B+8%5CS+=+97+%29%0D%0A++

Any system of equations:


has solution

or



(L=15, S=6.5}

CHECK:
Plug in equation 2
3L+8S=97kg
3(15kg)+8(6.5kg)=97kg
(45kg)+(52kg)=97kg
97kg=97kg

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
let b = the weight of a large box
let s = the weight of a small box
:
Write an equation for each statement
:
A delivery of 5 large boxes and 2 small boxes has a total weight of 88 kilograms.
5b + 2s = 88
:
A delivery of 3 large boxes and 8 small boxes has a total weight of 97 kilograms.
3b + 8s = 97
:
multiply the 1st equation by 4, subtract the 2nd equation
20b + 8s = 352
3b + 8s = 97
-----------------Subtraction eliminates s, find b
17b = 255
b = 255/17
b = 15 kg, the weight of the large box
:
Find s
3(15) + 8s = 97
45 + 8s = 97
8s = 97 - 45
8s = 52
s = 52/8
s = 6.5 kg, the weight of the small box
:
:
Check this in the 1st original equation; 5b + 2s = 88
5(15) + 2(6.5) = 88
75 + 13 = 88