SOLUTION: After the morning rush at the neighborhood coffee shop, the tip jar contained $3.75 in coins. There was one less quarter than nickels. There are twice as many dimes as nickels. How

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: After the morning rush at the neighborhood coffee shop, the tip jar contained $3.75 in coins. There was one less quarter than nickels. There are twice as many dimes as nickels. How      Log On

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Question 800980: After the morning rush at the neighborhood coffee shop, the tip jar contained $3.75 in coins. There was one less quarter than nickels. There are twice as many dimes as nickels. How many coins of each type were there?
Found 2 solutions by mananth, Finavon:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Nickels n
Dimes = 2n
quarter = (n-1)
375 cents total
5n+10*2n+25(n-1)=375
5n+20n+25n-25=375
50n-25=375
50n=400
n=400/50
n=8
Nickels = 8
dimes = 8*2=16
Quarter = (8-1) =7
Check
8*5+16*10+25*7=375

Answer by Finavon(81) About Me  (Show Source):
You can put this solution on YOUR website!
let q, n and d be number of each coin, worth 25c, 5c and 10c
25q+5n+10d=375
q=n-1
2n=d
substitute for d and q
25n-25+5n+20n = 375
50n=400 so n=8
then d=16 and q=7
8 nickels, 16 dimes and 7 quarters
Check: 25*7 + 5*8 + 10*16 = 175+40+160 = 375