SOLUTION: Gladys rents a car for $100 a week plus $0.10 per mile. What is the farthest she can drive to spend no more than $175? I know its 750 miles but I don't know how to write the prob
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Question 799972: Gladys rents a car for $100 a week plus $0.10 per mile. What is the farthest she can drive to spend no more than $175? I know its 750 miles but I don't know how to write the problem out. (Algebra inequalities) Answer by jerryguo41(197) (Show Source):
You can put this solution on YOUR website! Lets make C=Cost of renting the car, m=miles driven
So the relationship of C in terms of m would be: \
If she only rented the car for a week.
Otherwise another w=week variable will be added.
This equation can not be solved unless a number of weeks is given, so lets presume she drove it all in one week.
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Inserting C=175 which is the total amount spent
Subtracting 100 from each side
Divide by 0.1 which is also equal to multiplying bu 10.
So Glandy can drive a total of 750 miles if she drives in one week.
