SOLUTION: find a number A such that if X>A then X^2 > 10^16

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Question 440063: find a number A such that if X>A then
X^2 > 10^16
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
If x%5E2+%3E+10%5E16, then the solution set is x+%3C+-10%5E8 or x%3E+10%5E8, hence let A=+10%5E8.