SOLUTION: A jeweler needs to mix an alloy with a 16% gold content and an alloy with a 28% gold content to obtain 32 ounces of a new alloy with a 25% gold content. How many ounces of each of
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Question 446869: A jeweler needs to mix an alloy with a 16% gold content and an alloy with a 28% gold content to obtain 32 ounces of a new alloy with a 25% gold content. How many ounces of each of the original alloys must be used? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! A jeweler needs to mix an alloy with a 16% gold content and an alloy with a 28% gold content to obtain 32 ounces of a new alloy with a 25% gold content. How many ounces of each of the original alloys must be used?
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Let x = amount (ounces) of 16%
then
32-x = amount (ounces) of 28%
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.16x + .28(32-x) = .25(32)
.16x + 8.96 - .28x = 8
8.96 - .12x = 8
-.12x = -0.96
x = 8 ounces (of 16% gold content)
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28% gold content:
32-x = 32-8 = 24 ounces
