SOLUTION: A 10-quart radiator contains a 30% concentration of antifreeze. how much of the sloution must be drained and replaced by 100% antifreeze to bring the solution up to 50%
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Question 419707: A 10-quart radiator contains a 30% concentration of antifreeze. how much of the sloution must be drained and replaced by 100% antifreeze to bring the solution up to 50% Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 100 ---------------- x
30 ---------------- 10-x
50.00% ---------------- 10
...
100x +30(10 -x) = 50 * 10
100x +300-30 x= 500
100x-30 x=500- 300
70 x - = 200
/70
x=2.86 liters of 100.00%
2.86 liters of 30 % will have to be drained off.
