SOLUTION: How much of a 50% solution would have to be added to a 20% solution to make 24 liters of a 30% solution ?

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Question 372093: How much of a 50% solution would have to be added to a 20% solution to make 24 liters of a 30% solution ?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x represent the total amount of 50% solution. 

Then(24L-x) would be the amount of the 20% solution.

.50x + .20(24L-x) = .30*24L

solving for x

.50x + .20*24L - .20x = .30*24L

.30x = .10*24L

x = 8L of the 50% solution



checking our answer

(16L of the 20% solution (24-8)

.50*8 + .20*16 = 4 + 3.2 = 7.2= .30*24