SOLUTION: A coffee manufacturer wants to market a new blend of coffee that sells for $3.90 per pound by mixing two coffees that sell for $2.75 and $5 per pound,respectively.What amounts of e

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A coffee manufacturer wants to market a new blend of coffee that sells for $3.90 per pound by mixing two coffees that sell for $2.75 and $5 per pound,respectively.What amounts of e      Log On

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Question 1207744: A coffee manufacturer wants to market a new blend of coffee that sells for $3.90 per pound by mixing two coffees that sell for $2.75 and $5 per pound,respectively.What amounts of each coffee should be blended to obtain the desired mixture?
[Hint:Assume that the total weight of the desired blend is 100 pounds.]

Let me see.

Let x = one type of coffee
Let y = another type of coffee

Here is my set up:
a + b = 100
2.75a + 5.00b = 100(3.90)

Is this correct?

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
                   PRICE        POUNDS           COST

lowpriced           2.75        100-h           2.75(100-h)

highpriced          5             h             5h

result              3.9         100             5h+2.75(100-h)

Using h for the amount of the $5 per pound coffee, ....

This equation formed: 3.9%2A100=5h%2B2.75h%28100-h%29;
Solve for h, and evaluate 100-h.

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You already knew what to do.

Answer by ikleyn(52772) About Me  (Show Source):
You can put this solution on YOUR website!
.

Your set up is correct.

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It is a standard and typical mixture problem.

To see many similar problems solved with detailed explanations,  look into the lessons
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Typical word problems on mixtures from the archive
in this site.     Learn the subject from there.