SOLUTION: I have a Product we will call Product A which contains 98.078% water, .8970% of ingredient 1, .064% of ingredient 2, .064% of Ingredient 3, .7690% of ingredient 4 and .128% of Ingr

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Question 1083300: I have a Product we will call Product A which contains 98.078% water, .8970% of ingredient 1, .064% of ingredient 2, .064% of Ingredient 3, .7690% of ingredient 4 and .128% of Ingredient 5.
I want to make Product B which will be PRODUCT A plus X amount of water to dilute it.
How do I figure out the percentage of each of the ingredients in Product B the new more diluted product?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Q amount of product A
X amount of water to add to form product B
p PERCENT CONCENTRATION OF ANY ingredient in product A

Assuming concentrations are weight per volume (or "mass" per volume):
p%28Q%2F%28Q%2BX%29%29, percent concentration of the particular chosen ingredient in product B.