SOLUTION: Since 1953, Frank has gained two pounds every year. In 1983 he was 40% heavier than in 1953. What percent of his 1998 weight was his 1988 weight? I'm really sorry - I wasn't sure

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Question 913748: Since 1953, Frank has gained two pounds every year. In 1983 he was 40% heavier than in 1953. What percent of his 1998 weight was his 1988 weight?
I'm really sorry - I wasn't sure which category to put this question in.
Thank you in advance.

Answer by KMST(5347) About Me  (Show Source):
You can put this solution on YOUR website!
t= years since 1953.
W%28t%29= Frank's weight at time t (in pounds).
W%5B0%5D= Frank's weight (in pounds) at t=0 (1953).
W%28t%29=W%5B0%5D%2B2t , because he's been gaining 2 pounds per year since 1953.

For 1983:
t=1983-1953=30 and Frank's weight that year is
W%2830%29=W%5B0%5D%2B2%2A30=W%5B0%5D%2B60 .
The problem tells us that W%2830%29=W%5B0%5D%2B60 is 140% of Frank's 1953 weight, or 1.40W%5B0%5D , so
1.40W%5B0%5D=W%5B0%5D%2B60 is our first equation.
1.40W%5B0%5D=W%5B0%5D%2B60--->1.40W%5B0%5D-W%5B0%5D=60--->%281.4-1%29W%5B0%5D=60--->0.4W%5B0%5D=60--->W%5B0%5D=60%2F0.4--->W%5B0%5D=150 .
So Frank weighed W%5B0%5D=150pounds in 1953,
and he gained 2 pound per year after that, so
W%28t%29=150%2B2t

For 1998:
t=1998-1953=45 and Frank's weight that year is
W%2845%29=150%2B2%2A45--->W%2845%29=150%2B90--->W%2845%29=240 .
So Frank weighed W%5B45%5D=240pounds in 1998.

For 1988:
t=1988-1953=35 and Frank's weight that year is
W%2835%29=150%2B2%2A35--->W%2845%29=150%2B70--->W%2845%29=220 .
So Frank weighed W%5B35%5D=220pounds in 1988.

What fraction and what percentage of 240 is 220 ?
As a fraction, it is 220%2F240=11%2F12=+%220.91666+...%22 .
As a percentage, it is %2291.666+...%22%22%25%22 = about highlight%28%2292+%25%22%29