SOLUTION: A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled $487. The second order was for 6 bushes and 2 trees, and totaled

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled $487. The second order was for 6 bushes and 2 trees, and totaled       Log On

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Question 662148: A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled $487. The second order was for 6 bushes and 2 trees, and totaled $232. The bills do not list the per-item price. What were the costs of one bush and of one tree? Equation
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
13 bushes and 4 trees, and totaled $487
6 bushes and 2 trees, and totaled $232.
What were the costs of one bush highlight%28x%29and of one treehighlight%28y%29
Question states***
13x + 4y = 487
6x + 2y = 232 ||Multiplying 2nd EQ by 2, and subtracting to eliminate y
x = $23, cost of one bush. Tree costs $47 %28232-6%2A23%29%2F2
and...
13%2A23+%2B+4%2A47 = $487