SOLUTION: A pigeon flying against the wind flew 2 miles in 30 min. It made the return flight with the same wind in 20 min. Find the rate of the pigeon in still air.

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A pigeon flying against the wind flew 2 miles in 30 min. It made the return flight with the same wind in 20 min. Find the rate of the pigeon in still air.       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 395746: A pigeon flying against the wind flew 2 miles in 30 min. It made the return flight with the same wind in 20 min. Find the rate of the pigeon in still air.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A pigeon flying against the wind flew 2 miles in 30 min. It made the return flight with the same wind in 20 min. Find the rate of the pigeon in still air.
---------------
2 mi in 1/2 hour = 4 mph
2 mi in 1/3 hour = 6 mph
The pigeon's airspeed is the average (4+6)/2 = 5 mph