SOLUTION: An arrow is fired straight upward from the ground level with an initials velocity of 208ft per second. During which interval of time will the arrows height exceed 192 ft? Us the po

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Question 368388: An arrow is fired straight upward from the ground level with an initials velocity of 208ft per second. During which interval of time will the arrows height exceed 192 ft? Us the position formula: s=-16^2+vot+so
(vo=initial velocity, so= initial position, t=time)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find both values for t when s=192.
s=-16t%5E2%2B208t%2B0=192
16t%5E2-208t%2B192=0
t%5E2-13t%2B12=0
%28t-12%29%28t-1%29=0
Clearly the two solutions are t=1 and t=12.
DELTA%2At=12-1=highlight%2811%29seconds.