Question 161872: Find a five-digit number in which the first and last digits are the same and the first digit is two less than the second and four less than the third.
The fourth digit is one-fourth of the third digit.
The sum of the first and las digits equals the third digit.
If possible, please show the work. thanks!
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Write equation for each statement:
;
Find a five-digit number in which the first and last digits are the same.
Let w = 1st and last digits
:
Let the 5 digits = w, x, y, z, w
;
The first digit is two less than the second and four less than the third.
w = x - 2
or
x = w + 2
and
w = y - 4
or
y = w + 4
;
The fourth digit is one-fourth of the third digit.
z =  y
or
y = 4z
;
The sum of the first and last digits equals the third digit.
2w = y
:
From the 2nd statement, we know y = w+4, so we have:
2w = w+4
2w - w = 4
w = 4
:
y = w + 4
y = 4 + 4
y = 8
and
x = w + 2
x = 4 + 2
x = 2
and
z = y
z = 8
z = 2
;
The 5 digits;
4, 2, 8, 2, 4
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