SOLUTION: The perimeter of a rectangular garden is 98 feet. The length of the garden is 4 feet more than twice the width. What is the length of the garden?

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Question 134769: The perimeter of a rectangular garden is 98 feet. The length of the garden is 4 feet more than twice the width. What is the length of the garden?
Found 2 solutions by cbcrawford978, solver91311:
Answer by cbcrawford978(7) About Me  (Show Source):
You can put this solution on YOUR website!
P=98............P=2L+2W
L=length
W=width
P=perimeter
x=unknown
L=2W+4
P=(2W+4)+(2w+4)+(W)+(W)
P=6W+8
6W+8=98............6W=90.....W=15
L=2(15)+4........L=30+4
Length=34 feet

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
The length (L) of the garden is (=) 4 feet more (+) than twice (2 times) the width (W), or:

L=2W%2B4

The perimeter of a rectangle is P=2L+%2B+2W, but since we know that L=2W%2B4, we can write:

P=2%282W%2B4%29+%2B+2W.

Furthermore, since we are given that the perimeter is 98 feet we can write:

2%282W%2B4%29+%2B+2W+=+98

Now all you need to do is solve the equation for W. Once you have a value for W, substitute it into L=2W%2B4 then calculate L.