SOLUTION: The speed of light is 300,000km/sec and the planet Pluto is located at a distance of 6 billion km from Earth. If a spaceship, traveling at a constant speed in a straight line, goes

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The speed of light is 300,000km/sec and the planet Pluto is located at a distance of 6 billion km from Earth. If a spaceship, traveling at a constant speed in a straight line, goes      Log On

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Question 1205494: The speed of light is 300,000km/sec and the planet Pluto is located at a distance of 6 billion km from Earth. If a spaceship, traveling at a constant speed in a straight line, goes from Earth to Pluto in 100 hours, at what fraction of the speed of light is this spaceship travelling? Thank You!

Found 3 solutions by greenestamps, math_tutor2020, josgarithmetic:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


100 hours = 100*60 minutes = 100*60*60 seconds.

Divide the distance of 6 billion km by that number of seconds to find the speed of the spaceship in km/sec.

Divide that speed by the speed of light (both in km/sec) to get the answer.

You can do the calculations; use a calculator if needed.

ANSWER: You should get an answer of 1/18....


Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

300,000 = 3*10^5
6 billion = 6*10^9

1 hour = 60*60 = 3600 seconds
100 hours = 100*3600 = 360,000 seconds
360,000 = 3.6*10^5

Determine the speed of the spaceship
distance = rate*time
rate = distance/time
rate = (6*10^9 km)/(3.6*10^5 seconds)
rate = (6/3.6)*((10^9)/(10^5)) km per second
rate = (60/36)*10^4 km per second
rate = (5/3)*10^4 km per second

Divide this over the speed of light to wrap things up
( spaceship's speed )/( speed of light )
( (5/3)*10^4 )/( 3*10^5 )
( (5/3)*10^4 )/( 3*10*10^4 )
( (5/3)*10^4 )/( 30*10^4 )
( (5/3)/30 )*((10^4)/(10^4))
(5/3)/30
(5/3)*(1/30)
5/90
1/18 is the final answer.

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Another approach

Let's see how long it takes a light beam to go from Earth to Pluto
distance = rate*time
time = distance/rate
time = (6*10^9 km)/(3*10^5 km per sec)
time = (6/3)*((10^9)/(10^5)) sec
time = 2*10^4 sec
time = 20,000 sec

Divide this over 360,000 seconds (the time it takes the spaceship to reach Pluto) and you should get the fraction 1/18
It represents the idea that the light beam can travel to Pluto 18 times in the same timespan the spaceship travels.
In other words, the light beam travels 18/2 = 9 round trips from Earth to Pluto, and back. In these 9 round trips of the light beam, the spaceship will arrive at Pluto.

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Answer: 1/18

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
THE SPACESHIP
%28%286000000000%2Akm%29%2F%28100%2Ahr%29%29%281%2F3600%29%28hr%2Fseconds%29
%286000000000%29%2F%28360000%29%28km%2Fsecond%29
600000%2F36km%2Fsecond
100000%2F6km%2Fsecond
16666%262%2F3km%2Fsecond

COMPARE TO LIGHT SPEED
%2816666%262%2F3%29%2F300000
0.0555555555555...
50000%2F900000
highlight%281%2F18%29---------as fraction of speed of light